Sunday 6 September 2026 Rebuilt nightly from the WCA's official results · export of 6 September 2026 · About
The Middle Three
People → Brazil → Caio Hokama Freitas

People · Brazil

Caio Hokama Freitas

3×3 · top 16.1% of 284,439 all-time · competing since July 2015 · 2015FREI02

Caio Hokama Freitas has been competing for 11 years. His best event is the 3×3: a personal-best single of 12.61, set at Fecap Open 2022, puts him in the top 16.1% of the 284,439 people who have ever been ranked in the event, and 857th in Brazil. Across 2 competitions since July 2015, he has put 15 official solves on the record across two events. His 3×3 best has come down from 34.93 in July 2015 to 12.61, a 64% improvement. Caio has entered two competitions.

3×3
best event — top 16.1% of 284,439 all-time
12.61
signature single · Fecap Open 2022
15
official solves on the record

Standing, event by event

vs everyone ever ranked
EventPB singlePB averageAll-time standingBrazil
3×312.6114.85
top 16.1%857 / 9,644
Skewb9.1818.30
top 49.6%632 / 1,463

Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.

The line so far

World Rubik's Cube Championship 2015: 34.93Fecap Open 2022: 12.6112.6134.9317 Jul 20158 Oct 2022

Best single per competition, 3×3. Faster is higher — the axis is the right way up.

The story so far

Competitions

Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.

The circuit

The people whose scorecards keep turning up next to his.

Next targets

  • A sub-12 3×3 single — 39,535 people have one; it is 0.61 away.
  • A sub-8 Skewb single — 30,246 people have one; it is 1.18 away.

Targets move as he improves.