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People → China → Zitao Li (李子滔)

People · China

Zitao Li (李子滔)

3×3 · top 4.2% of 288,433 all-time · competing since February 2026 · 2026LIZI04

Zitao Li (李子滔) has been competing for 9 months. His best event is the 3×3: a personal-best single of 8.72, set at Foshan Open 2026, puts him in the top 4.2% of the 288,433 people who have ever been ranked in the event, and 1,647th in China. Until May 2008, no official 3×3 solve in the world had been that fast. Across 4 competitions since February 2026, he has put 35 official solves on the record across one event. Solve to solve, his 3×3 times vary about 12% around a typical one, an early reading from 7 counted rounds. His 3×3 best has come down from 10.85 in February 2026 to 8.72, a 20% improvement. Zitao has entered four competitions, more competitions than 78% of everyone who has ever competed.

3×3
best event — top 4.2% of 288,433 all-time
8.72
signature single · Foshan Open 2026
35
official solves on the record

Standing, event by event

vs everyone ever ranked
EventPB singlePB averageAll-time standingChina
3×38.7210.21
top 4.2%1,647 / 28,499

Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.

The line so far

Guangdong Open - Revival & Rival 2026: 10.85Foshan Open 2026: 8.72Guangzhou GraDUAL 3x3 II 2026: 9.62Guangzhou Grand Open 2026: 9.408.7210.856 Feb 20265 Oct 2026

Best single per competition, 3×3. Faster is higher — the axis is the right way up.

The story so far

Competitions

Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.

The circuit

The people whose scorecards keep turning up next to his.

Next targets

Targets move as he improves.