People · China
Yuanqi Xia (夏园淇)
3×3 · top 50.4% of 284,439 all-time · competing since July 2013 · 2013XIAY01
Yuanqi Xia (夏园淇) has been competing for 13 years. His best event is the 3×3: a personal-best single of 24.02, set at Guangzhou CCSA Championship 2013, puts him in the top 50.4% of the 284,439 people who have ever been ranked in the event, and 16,194th in China. Across 2 competitions since July 2013, he has put 20 official solves on the record across two events. Yuanqi has entered two competitions.
Standing, event by event
vs everyone ever ranked| Event | PB single | PB average | All-time standing | China | |
|---|---|---|---|---|---|
| 3×3 | 24.02 | 28.04 | top 50.4% | 16,194 / 28,153 | |
| 2×2 | 8.43 | 13.29 | top 70.4% | 11,554 / 15,796 |
Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.
The line so far
Best single per competition, 3×3. Faster is higher — the axis is the right way up.
The story so far
- 22 Jul 2013First competition: Guangzhou CCSA Championship 2013. A 24.02 3×3 single to start from.
Competitions
- Guangdong Open 2013 · 1 Oct 2013 — 1 personal best set
- Guangzhou CCSA Championship 2013 · 22 Jul 2013
Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.
The circuit
The people whose scorecards keep turning up next to his.
- Aiying Guo (郭蔼盈) — met in 4 rounds, finished ahead 4 times
- Lang Cao (曹朗) — met in 4 rounds, finished ahead 3 times
- Junyuan Huang (黄俊源) — met in 4 rounds, finished ahead twice
Next targets
- A sub-20 3×3 single — 113,584 people have one; it is 4.02 away.
- A sub-8 2×2 single — 126,624 people have one; it is 0.43 away.
Targets move as he improves.