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People → China → Wentao Song (宋文韬)

People · China

Wentao Song (宋文韬)

3×3 blindfolded · top 1.2% of 12,178 all-time · competing since June 2024 · 2024SONG15

Wentao Song (宋文韬) has been competing for 2 years. His best event is the 3×3 blindfolded: a personal-best single of 19.46, set at Please Be Quiet Beijing 2024, puts him in the top 1.2% of the 12,178 people who have ever been ranked in the event, and 14th in China. Until November 2016, no official 3×3 blindfolded solve in the world had been that fast. Across 2 competitions since June 2024, he has put 9 official solves on the record across two events. His 3×3 blindfolded best has come down from 22.85 in June 2024 to 19.46, a 15% improvement. Wentao has entered two competitions.

3×3 blindfolded
best event — top 1.2% of 12,178 all-time
19.46
signature single · Please Be Quiet Beijing 2024
9
official solves on the record

Standing, event by event

vs everyone ever ranked
EventPB singlePB averageAll-time standingChina
3×3 blindfolded19.46
top 1.2%14 / 1,183
3×3 Multi-Blind8 of 10 cubes · 40:07
early days — 2 solves85 / 278

Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.

The line so far

Tianjin Open 2024: 22.85Please Be Quiet Beijing 2024: 19.4619.4622.851 Jun 202418 Aug 2024

Best single per competition, 3×3 blindfolded. Faster is higher — the axis is the right way up.

The story so far

Competitions

Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.

The circuit

The people whose scorecards keep turning up next to his.

Next targets

  • A sub-15 3×3 blindfolded single — 19 people have one; it is 4.46 away.

Targets move as he improves.