People · China
Wenfan Zhong (钟文梵)
3×3 · top 40.9% of 288,433 all-time · competing since November 2018 · 2018ZHON17
Wenfan Zhong (钟文梵) has been competing for 8 years. His best event is the 3×3: a personal-best single of 20.30, set at Chongqing Open 2018, puts him in the top 40.9% of the 288,433 people who have ever been ranked in the event, and 14,215th in China. Across 2 competitions since November 2018, he has put 15 official solves on the record across one event. His 3×3 best has come down from 31.59 in November 2018 to 20.30, a 36% improvement. Wenfan has entered two competitions.
Standing, event by event
vs everyone ever ranked| Event | PB single | PB average | All-time standing | China | |
|---|---|---|---|---|---|
| 3×3 | 20.30 | 25.15 | top 40.9% | 14,215 / 28,499 |
Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.
The line so far
Best single per competition, 3×3. Faster is higher — the axis is the right way up.
The story so far
- 8 Dec 2018First sub-30 3×3: 21.06 at Chongqing Open 2018.
- 24 Nov 2018First competition: Chengdu Winter Open 2018. A 31.59 3×3 single to start from.
Competitions
- Chongqing Open 2018 · 8 Dec 2018 — 2 personal bests set
- Chengdu Winter Open 2018 · 24 Nov 2018
Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.
The circuit
The people whose scorecards keep turning up next to his.
- Jiafeng Peng (彭嘉锋) — met in 3 rounds, finished ahead twice
- Haoyu Jiang (蒋昊宇) — met in 3 rounds, finished ahead once
- Haoyan Meng (孟昊岩) — met in 3 rounds, finished ahead once
Next targets
- A sub-20 3×3 single — 115,495 people have one; it is 0.30 away.
Targets move as he improves.