People · Australia
Ved Parmar
3×3 · top 57.7% of 284,439 all-time · competing since July 2025 · 2025PARM03
Ved Parmar has been competing for a year. His best event is the 3×3: a personal-best single of 27.44, set at Puzzling Pakenham Sunday 2025, puts him in the top 57.7% of the 284,439 people who have ever been ranked in the event, and 6,220th in Australia. Across 2 competitions since July 2025, he has put 15 official solves on the record across one event. His 3×3 best has come down from 38.67 in July 2025 to 27.44, a 29% improvement. Ved has entered two competitions.
Standing, event by event
vs everyone ever ranked| Event | PB single | PB average | All-time standing | Australia | |
|---|---|---|---|---|---|
| 3×3 | 27.44 | 30.44 | top 57.7% | 6,220 / 11,709 |
Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.
The line so far
Best single per competition, 3×3. Faster is higher — the axis is the right way up.
The story so far
- 28 Sep 2025First sub-30 3×3: 27.44 at Puzzling Pakenham Sunday 2025.
- 26 Jul 2025First competition: Spark Melbourne July 2025. A 38.67 3×3 single to start from.
Competitions
- Puzzling Pakenham Sunday 2025 · 28 Sep 2025 — 1 personal best set
- Spark Melbourne July 2025 · 26 Jul 2025
Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.
The circuit
The people whose scorecards keep turning up next to his.
- Arvin Eshragh — met in 3 rounds, finished ahead once
- Keaton Ellis — met in 3 rounds, never finished ahead
- Tommy Kiprillis — met in 3 rounds, never finished ahead
Next targets
- A sub-25 3×3 single — 149,621 people have one; it is 2.44 away.
Targets move as he improves.