People · Portugal
Tiago Leite
2×2 · top 48.5% of 186,767 all-time · competing since May 2025 · 2025LEIT01
Tiago Leite has been competing for a year. His best event is the 2×2: a personal-best single of 5.78, set at CNSE ao Cubo 2025, puts him in the top 48.5% of the 186,767 people who have ever been ranked in the event, and 217th in Portugal. Across 2 competitions since May 2025, he has put 21 official solves on the record across three events. Tiago has entered two competitions.
Standing, event by event
vs everyone ever ranked| Event | PB single | PB average | All-time standing | Portugal | |
|---|---|---|---|---|---|
| 2×2 | 5.78 | 17.24 | top 48.5% | 217 / 417 | |
| 3×3 | 23.83 | 29.98 | top 49.9% | 297 / 547 | |
| 5×5 | 3:34.64 | — | early days — 2 solves | 88 / 110 |
Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.
The line so far
Best single per competition, 2×2. Faster is higher — the axis is the right way up.
The story so far
- 3 May 2025First competition: CNSE ao Cubo 2025. A 26.99 3×3 single to start from.
Competitions
- Felgueiras ao Cubo 2026 · 25 Apr 2026 — 1 personal best set
- CNSE ao Cubo 2025 · 3 May 2025
Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.
The circuit
The people whose scorecards keep turning up next to his.
- António Gomes — met in 5 rounds, never finished ahead
- Bernardo Leite da Cunha — met in 5 rounds, never finished ahead
- Rui Alexandre Reis Lopes — met in 5 rounds, never finished ahead
Next targets
- A sub-5 2×2 single — 73,413 people have one; it is 0.78 away.
- A sub-20 3×3 single — 113,584 people have one; it is 3.83 away.
Targets move as he improves.