People · India
Riaan Narula
2×2 · top 39.2% of 186,767 all-time · competing since November 2024 · 2024NARU01
Riaan Narula has been competing for a year. His best event is the 2×2: a personal-best single of 4.99, set at Shri Ram Cubing Challenge 2025, puts him in the top 39.2% of the 186,767 people who have ever been ranked in the event, and 3,620th in India. Across 2 competitions since November 2024, he has put 25 official solves on the record across three events. Riaan has entered two competitions.
Standing, event by event
vs everyone ever ranked| Event | PB single | PB average | All-time standing | India | |
|---|---|---|---|---|---|
| 2×2 | 4.99 | 6.62 | top 39.2% | 3,620 / 12,146 | |
| 3×3 | 23.92 | 30.75 | top 50.2% | 7,487 / 20,018 | |
| Pyraminx | 10.46 | 14.81 | top 56.5% | 3,827 / 8,934 |
Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.
The line so far
Best single per competition, 2×2. Faster is higher — the axis is the right way up.
The story so far
- 9 Nov 2024First competition: Delhi Cube Challenge 2024.
Competitions
- Shri Ram Cubing Challenge 2025 · 22 Mar 2025 — 1 personal best set
- Delhi Cube Challenge 2024 · 9 Nov 2024
Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.
The circuit
The people whose scorecards keep turning up next to his.
- Atharva Goel — met in 5 rounds, finished ahead 5 times
- Abhijit Verma — met in 5 rounds, finished ahead 4 times
- Pranav Taneja — met in 5 rounds, finished ahead 4 times
Next targets
- A sub-4 2×2 single — 49,452 people have one; it is 0.99 away.
- A sub-20 3×3 single — 113,584 people have one; it is 3.92 away.
Targets move as he improves.