People · China
Haien Li (李海恩)
3×3 · top 5.5% of 284,439 all-time · competing since May 2026 · 2026LIHA05
Haien Li (李海恩) has been competing for 4 months. Her best event is the 3×3: a personal-best single of 9.25, set at Start of Summer Beijing 2026, puts her in the top 5.5% of the 284,439 people who have ever been ranked in the event, and 2,120th in China. Until February 2008, no official 3×3 solve in the world had been that fast. Across 1 competition since May 2026, she has put 25 official solves on the record across three events.
Standing, event by event
vs everyone ever ranked| Event | PB single | PB average | All-time standing | China | |
|---|---|---|---|---|---|
| 3×3 | 9.25 | 11.30 | top 5.5% | 2,120 / 28,153 | |
| 4×4 | 44.76 | 52.96 | top 18.0% | 1,955 / 5,926 | |
| 2×2 | 4.37 | 5.15 | top 31.3% | 5,353 / 15,796 |
Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.
The story so far
- 1 May 2026First competition: Start of Summer Beijing 2026. A 10.61 3×3 single to start from.
- 1 May 2026First sub-10 3×3: 9.25 at Start of Summer Beijing 2026.
Competitions
- Start of Summer Beijing 2026 · 1 May 2026 — 2 personal bests set
Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.
The circuit
The people whose scorecards keep turning up next to her.
- Kangzhan Wei (魏康展) — met in 5 rounds, finished ahead 4 times
- Dehao Kong (孔德淏) — met in 5 rounds, finished ahead 4 times
- Chenfei Yan (鄢辰飞) — met in 5 rounds, finished ahead 4 times
Next targets
- A sub-8 3×3 single — 7,931 people have one; it is 1.25 away.
- A sub-40 4×4 single — 10,180 people have one; it is 4.76 away.
Targets move as she improves.