People · India
Amrinder Jeet Singh
3×3 · top 40.0% of 284,439 all-time · competing since January 2017 · 2017SING02
Amrinder Jeet Singh has been competing for 10 years. His best event is the 3×3: a personal-best single of 20.03, set at MathSoc Open 2017, puts him in the top 40.0% of the 284,439 people who have ever been ranked in the event, and 5,656th in India. Across 1 competition since January 2017, he has put 17 official solves on the record across four events.
Standing, event by event
vs everyone ever ranked| Event | PB single | PB average | All-time standing | India | |
|---|---|---|---|---|---|
| 3×3 | 20.03 | 23.36 | top 40.0% | 5,656 / 20,018 | |
| 2×2 | 8.54 | 12.97 | top 71.0% | 7,360 / 12,146 | |
| Pyraminx | 18.53 | 23.01 | top 90.8% | 7,333 / 8,934 | |
| 3×3 one-handed | 1:21.05 | — | early days — 2 solves | 4,008 / 4,516 |
Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.
The story so far
- 21 Jan 2017First competition: MathSoc Open 2017. A 20.03 3×3 single to start from.
Competitions
- MathSoc Open 2017 · 21 Jan 2017
Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.
The circuit
The people whose scorecards keep turning up next to his.
- Hardik Arya — met in 4 rounds, finished ahead 4 times
- Sahil Aggarwal — met in 4 rounds, finished ahead 3 times
- Ashmit Arya — met in 4 rounds, finished ahead 3 times
Next targets
- A sub-20 3×3 single — 113,584 people have one; it is 0.03 away.
- A sub-8 2×2 single — 126,624 people have one; it is 0.54 away.
Targets move as he improves.