People · India
Akshat Tiwary
3×3 · top 90.4% of 284,439 all-time · competing since November 2024 · 2024TIWA07
Akshat Tiwary has been competing for a year. His best event is the 3×3: a personal-best single of 57.42, set at Delhi Cube Challenge 2024, puts him in the top 90.4% of the 284,439 people who have ever been ranked in the event, and 16,023rd in India. Across 1 competition since November 2024, he has put 9 official solves on the record across two events.
Standing, event by event
vs everyone ever ranked| Event | PB single | PB average | All-time standing | India | |
|---|---|---|---|---|---|
| 3×3 | 57.42 | 1:10.54 | top 90.4% | 16,023 / 20,018 | |
| 2×2 | 29.04 | 40.65 | top 98.6% | 11,702 / 12,146 |
Percentile against all competitors ever ranked in each event, a fairer measure than raw rank, because the pools differ by a factor of ten.
The story so far
- 9 Nov 2024First competition: Delhi Cube Challenge 2024. A 57.42 3×3 single to start from.
Competitions
- Delhi Cube Challenge 2024 · 9 Nov 2024
Reading this page: a single is one solve's time · an average is the middle three of five solves, best and worst discarded · a PB is a personal best · a DNF (did not finish) is an attempt with no valid result: a popped piece, an unsolved face, an over-limit memorisation · top X% compares against everyone ever ranked in that event, which is fairer than raw rank because event pools differ tenfold.
Next targets
- A sub-50 3×3 single — 244,718 people have one; it is 7.42 away.
- A sub-25 2×2 single — 182,590 people have one; it is 4.04 away.
Targets move as he improves.